Lesson 10: Function Overloading

Function Overloading\n\nC++ allows multiple functions with the same name but different signatures (parameter types, number, or const‑qualifiers). Overload resolution picks the best match based on the arguments supplied. Ambiguities arise when two overloads are equally viable.\n\n---\n\n## Example: Overloading based on parameter types\ncpp\nvoid print(int i) {\n std::cout << \"Integer: \" << i << '\\n';\n}\n\nvoid print(double d) {\n std::cout << \"Double: \" << d << '\\n';\n}\n\nvoid print(const std::string& s) {\n std::cout << \"String: \" << s << '\\n';\n}\n\nint main() {\n print(42); // calls int overload\n print(3.14); // calls double overload\n print(std::string(\"hi\")); // calls string overload\n return 0;\n}\n\n\nPitfall: If you add void print(long l); and call print(42);, the compiler may be ambiguous because both int and long are viable.\n\n> Tip: Use the explicit keyword on single‑argument constructors to avoid unintended implicit conversions.\n\n---\n\n<Alert type="warning">You cannot overload on return type alone; the return type is not considered in overload resolution.